States of matter; liquids and solids

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SUMMARY

The discussion focuses on the phase change of water at 0°C, specifically the evaporation and freezing processes under low pressure conditions. It establishes that when 9.31 g of ice is formed, approximately 1/7th of the original liquid water must have evaporated, based on the heat of fusion (6.01 kJ/mol) and heat of vaporization (44.9 kJ/mol) of water. This relationship highlights the significant energy difference required for vaporization compared to freezing, providing a clear understanding of the energy dynamics involved in these phase changes.

PREREQUISITES
  • Understanding of phase changes in matter
  • Knowledge of thermodynamics, specifically heat of fusion and heat of vaporization
  • Basic skills in stoichiometry and molar conversions
  • Familiarity with vacuum systems and their effects on boiling points
NEXT STEPS
  • Study the principles of thermodynamics related to phase changes
  • Learn about the calculations involving heat of fusion and heat of vaporization
  • Explore the effects of pressure on boiling points and phase transitions
  • Investigate the application of vacuum pumps in laboratory settings
USEFUL FOR

Students in chemistry, educators teaching phase change concepts, and professionals in scientific research focusing on thermodynamic properties of substances.

babysnatcher
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Water at 0°C was placed in a dish inside a vessel maintained at low pressure by a vacuum pump. After a quantiti of water had evaporated, the remainder froze. If 9.31 g of ice at 0°C was obtained, how much liquid water must have evaporated? The heat of fusion of water is 6.01 kJ/mol and its heat of vaoprization is 44.9 kJ/mol at 0°C.

Ok so I have conversion factors in specific places that coincedently generated the correct answer and I know this because my answer matches the books answer. But I don't understand the reasoning. Why does this work? I need to know what is really going on. And how to be able to know the answer is correct without peeking.
 
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babysnatcher said:
Water at 0°C was placed in a dish inside a vessel maintained at low pressure by a vacuum pump. After a quantiti of water had evaporated, the remainder froze. If 9.31 g of ice at 0°C was obtained, how much liquid water must have evaporated? The heat of fusion of water is 6.01 kJ/mol and its heat of vaoprization is 44.9 kJ/mol at 0°C.

Ok so I have conversion factors in specific places that coincedently generated the correct answer and I know this because my answer matches the books answer. But I don't understand the reasoning. Why does this work? I need to know what is really going on. And how to be able to know the answer is correct without peeking.

It seems you need just over 7 times the energy to vapourise the water than to freeze it, so around 1/7th will have evaporated when the rest has frozen.
 

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