- #1

- 10

- 0

## Homework Statement

A person who weighs 620 N stands at x = 5.00 m, right on the end of a long horizontal diving board that weighs 350 N. The diving board is held up by two supports, one at its left end at x = 0, and one at the point x = 2.00 m. (a) What is the force exerted on the support at x = 0? (b) What is the force acting on the other support? (Use positive to indicate an upward force, negative for a downward force.)

## Homework Equations

sum T=0, T=FR

Mgp=wieght of the person

Mgb=weight of the board

FA=force at point a - the left most support

FB=Force at point b - the rightmost support

## The Attempt at a Solution

I dont know what im doing wrong, but apparently these answers are incorrect.

(a) sum T= 0 =-Mgp*Rp+(-Mgb)*Rb+FA*Ra

FA=[Mgp*Rp+Mgb*Rb]/Ra

all about point b

FA=[620N*3m+350N*.5m]/-2m

FA=-1017.5N

(b)FB=[Mgp*Rp+Mgb*Rb]/Rb

about point a

FB=[620*5+350*2.5]/2

FB=1987.5