Static equilibrium, trusses/section method

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SUMMARY

The discussion focuses on calculating forces in members BC, BE, and EF of a truss using static equilibrium principles. Participants emphasize the importance of correctly identifying torques acting on point B, with two primary torques identified: Dy(5) and 2.5EFcos∅. The conversation also highlights the need to accurately determine distances and angles using the law of sines and trigonometric relationships, particularly in triangle CEP, to solve for unknown lengths such as CP.

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  • Understanding of static equilibrium principles in structural analysis
  • Familiarity with truss analysis and member force calculations
  • Knowledge of trigonometric functions and the law of sines
  • Ability to construct and analyze free body diagrams
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  • Study the method of joints for analyzing truss structures
  • Learn about the application of the law of sines in triangle calculations
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Engineering students, structural analysts, and professionals involved in civil engineering or mechanical design who are working on truss analysis and static equilibrium problems.

J-dizzal
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Homework Statement


Calculate the forces in members BC, BE, and EF. Solve for each force from an equilibrium equation which contains that force as the only unknown. The forces are positive if in tension, negative if in compression.
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Homework Equations


Sum of forces and moments equal zero.

The Attempt at a Solution


20150718_153056_zpsr4lvcjn7.jpg


I'm on force BE, i cannot see what is wrong with my moment equation. what am i missing here? thanks.
 
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How many torques are acting on B?
 
Dr. Courtney said:
How many torques are acting on B?
B has two torques acting on it.
 
Are you sure? Why only two?
 
Dr. Courtney said:
Are you sure? Why only two?
because i made a cut between B and C. and the only torques are: Dy(5) and 2.5EFcos∅
im sure i think its only two. but I am often wrong
 
Last edited:
Dr. Courtney said:
Are you sure? Why only two?
Should i include G(2.5)? if yes then why because i cut it out?
 
Your distance between D and P doesn't look correct.
 
TSny said:
Your distance between D and P doesn't look correct.
I created point P to be 2.5m from point D. was i wrong to do that?
edited
 
I thought you chose P so that P lies on the extension of segment FE. Then force FEF would not produce any moment about P.

If P is not on the extension of EF then you will need to include the moment due to FEF when summing moments about P.
 
  • #10
TSny said:
I thought you chose P so that P lies on the extension of segment FE. Then force FEF would not produce any moment about P.

If P is not on the extension of EF then you will need to include the moment due to FEF when summing moments about P.
Oh ok i get the trick now. that makes much more sense. let me try again. thanks
 
  • #11
J-dizzal said:
Oh ok i get the trick now. that makes much more sense. let me try again. thanks
so how do i find the length of DP if i only know the angles and one side of a similar triangle CED?
Is using similar triangles the correct way to solve for DP?
 
Last edited:
  • #12
Consider triangle CEP. What is the angle at vertex P? What is the length of side CP?
 
  • #13
TSny said:
Consider triangle CEP. What is the angle at vertex P? What is the length of side CP?
the angle at P is 17.74 degrees. I am still thinking about how to find length CP
 
  • #14
TSny said:
Consider triangle CEP. What is the angle at vertex P? What is the length of side CP?
CP is 5.8 using the law of sines.
 
  • #15
J-dizzal said:
the angle at P is 17.74 degrees. I am still thinking about how to find length CP
OK
 
  • #16
J-dizzal said:
CP is 5.8 using the law of sines.
I don't think this is correct. I don't see how you are using the law of sines.

If you know the angle at P and the length of the side CE, you should be able to get side CP.
 
  • #17
TSny said:
I don't think this is correct. I don't see how you are using the law of sines.

If you know the angle at P and the length of the side CE, you should be able to get side CP.

Im struggling to see how. I used the law of sines knowing two angles of CEP and one side.
sin(72.26)/CP = sin(17.74)/1.7
 
  • #18
J-dizzal said:
Im struggling to see how. I used the law of sines knowing two angles of CEP and one side.
sin(72.26)/CP = sin(17.74)/1.7
OK. That will work. But I don't get 5.8 for CP using this formula.

I was thinking of just using 1.7/CP = tan(17.74) to find CP.
 
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  • #19
TSny said:
OK. That will work. But I don't get 5.8 for CP using this formula.

I was thinking of just using 1.7/CP = tan(17.74) to find CP.
Yea i made an algebra mistake...i should of taken an algebra class this summer instead.
 

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