Static equilibrium, trusses/section method

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Homework Help Overview

The discussion revolves around calculating forces in members of a truss structure, specifically focusing on members BC, BE, and EF. The participants are exploring static equilibrium and the application of equilibrium equations to solve for unknown forces.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are discussing the number of torques acting on point B and questioning the validity of their assumptions regarding torque calculations. There are attempts to clarify the placement of point P and its implications on moment calculations. The use of similar triangles and the law of sines is also being explored to find lengths within the triangles formed by the truss members.

Discussion Status

The discussion is active with participants questioning each other's reasoning and calculations. Some guidance has been offered regarding the placement of point P and the use of trigonometric relationships. There is a recognition of algebraic mistakes, indicating a collaborative effort to clarify misunderstandings.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information available for their calculations. There is an emphasis on ensuring that all forces and moments are accounted for in their equilibrium equations.

J-dizzal
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Homework Statement


Calculate the forces in members BC, BE, and EF. Solve for each force from an equilibrium equation which contains that force as the only unknown. The forces are positive if in tension, negative if in compression.
20150718_153115_zps3gcjaafw.jpg

Homework Equations


Sum of forces and moments equal zero.

The Attempt at a Solution


20150718_153056_zpsr4lvcjn7.jpg


I'm on force BE, i cannot see what is wrong with my moment equation. what am i missing here? thanks.
 
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How many torques are acting on B?
 
Dr. Courtney said:
How many torques are acting on B?
B has two torques acting on it.
 
Are you sure? Why only two?
 
Dr. Courtney said:
Are you sure? Why only two?
because i made a cut between B and C. and the only torques are: Dy(5) and 2.5EFcos∅
im sure i think its only two. but I am often wrong
 
Last edited:
Dr. Courtney said:
Are you sure? Why only two?
Should i include G(2.5)? if yes then why because i cut it out?
 
Your distance between D and P doesn't look correct.
 
TSny said:
Your distance between D and P doesn't look correct.
I created point P to be 2.5m from point D. was i wrong to do that?
edited
 
I thought you chose P so that P lies on the extension of segment FE. Then force FEF would not produce any moment about P.

If P is not on the extension of EF then you will need to include the moment due to FEF when summing moments about P.
 
  • #10
TSny said:
I thought you chose P so that P lies on the extension of segment FE. Then force FEF would not produce any moment about P.

If P is not on the extension of EF then you will need to include the moment due to FEF when summing moments about P.
Oh ok i get the trick now. that makes much more sense. let me try again. thanks
 
  • #11
J-dizzal said:
Oh ok i get the trick now. that makes much more sense. let me try again. thanks
so how do i find the length of DP if i only know the angles and one side of a similar triangle CED?
Is using similar triangles the correct way to solve for DP?
 
Last edited:
  • #12
Consider triangle CEP. What is the angle at vertex P? What is the length of side CP?
 
  • #13
TSny said:
Consider triangle CEP. What is the angle at vertex P? What is the length of side CP?
the angle at P is 17.74 degrees. I am still thinking about how to find length CP
 
  • #14
TSny said:
Consider triangle CEP. What is the angle at vertex P? What is the length of side CP?
CP is 5.8 using the law of sines.
 
  • #15
J-dizzal said:
the angle at P is 17.74 degrees. I am still thinking about how to find length CP
OK
 
  • #16
J-dizzal said:
CP is 5.8 using the law of sines.
I don't think this is correct. I don't see how you are using the law of sines.

If you know the angle at P and the length of the side CE, you should be able to get side CP.
 
  • #17
TSny said:
I don't think this is correct. I don't see how you are using the law of sines.

If you know the angle at P and the length of the side CE, you should be able to get side CP.

Im struggling to see how. I used the law of sines knowing two angles of CEP and one side.
sin(72.26)/CP = sin(17.74)/1.7
 
  • #18
J-dizzal said:
Im struggling to see how. I used the law of sines knowing two angles of CEP and one side.
sin(72.26)/CP = sin(17.74)/1.7
OK. That will work. But I don't get 5.8 for CP using this formula.

I was thinking of just using 1.7/CP = tan(17.74) to find CP.
 
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  • #19
TSny said:
OK. That will work. But I don't get 5.8 for CP using this formula.

I was thinking of just using 1.7/CP = tan(17.74) to find CP.
Yea i made an algebra mistake...i should of taken an algebra class this summer instead.
 

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