Static Friction Question — A wood block sliding on a tabletop

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SUMMARY

The discussion centers on calculating the force of static friction for a wood block sliding on a tabletop. The user estimates the normal force (Fn) to be 17.64 N based on the weight of the block, calculated using the formula Fn = mass × gravity (1.8 kg × 9.80 m/s²). However, there is confusion regarding the application of this value, as it pertains to a block that is not in motion. The importance of drawing a free body diagram (FBD) is emphasized as a critical step in solving such physics problems.

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  • Familiarity with static friction concepts
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physicsstudent111
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Homework Statement
A 4.0 kg block of wood (m 1 ) sits on a level table. A string is tied to the wood and runs over a
frictionless pulley to a hanging object (as shown below). The greatest mass that can be hung
from the string (m 2 ) without moving the block of wood is 1.8 kg. Calculate the coefficient of
static frictions between the block of wood and the table.
Relevant Equations
F=uFn
Fg=Fn
I have no idea how to start this other than that I think that Fn is 17.64N and Fnet is 0. But I don't have the mew, so I am not sure how I am going to get the force of static friction.
 
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Welcome!
Please, tell us about what and for how long you have studied about this subject.
 
About a week. Do you have any suggestions for this question?
 
physicsstudent111 said:
About a week. Do you have any suggestions for this question?
Draw a free body diagram (FBD) for the block. They are the cat's mew for problems of this kind.
 
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What is Fn in that equation?
Show us how did you estimate that value of 17.64 N, please.
 
I assumed that Force of gravity is equal to Fn. So I did 1.8kg(9.80m/s(down))=17.64N. But I think this is wrong
 
Yes, you have calculated the weight of block #2, but that one is hanging in the air (no friction there).

pulley_prob_3.png
 
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