(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.25 with the floor. If the train is initially moving at a speed of 48 km/h, in how short a distance can the train be stopped at constant acceleration without causing the crates to slide over the floor?

2. Relevant equations

F = ma

f(s)max= u(s)N

final v^2-init. v^2 = 2a*s(distance)

Newton's second law?

3. The attempt at a solution

I've been cracking my skull on this one... I search and found this https://www.physicsforums.com/showthread.php?t=186380 however, I couldn't figure it out.

Is the maximum deceleration -.25g?

But when I plug that into: 0-13.33=2*a*s => -13.33/(-2*.25*9.8) = 2.72m and obviously something is wrong...

Thanks in advance.

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# Homework Help: Static Friction- Train stops, boxes move?

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