Statics Equilibrium Problem - 3 Force body in equilibrium

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Discussion Overview

The discussion revolves around a statics equilibrium problem involving a T-shaped bracket supporting a load. Participants are analyzing the reactions at points A and C under different angles (alpha = 90° and alpha = 45°) and attempting to reconcile their calculations with textbook answers.

Discussion Character

  • Homework-related, Debate/contested, Mathematical reasoning

Main Points Raised

  • One participant presents calculated values for reactions at A and C for both angles, suggesting A = 150 N down and C = 167.7 N at 63.4 degrees for alpha = 90°, and A = 194.5 N down and C = 253 N at 77.9 degrees for alpha = 45°.
  • Another participant attempts to use the sine law and a force triangle but finds their results for A and C to be double the expected values, leading to confusion about their approach.
  • A third participant suggests taking moments about point C, leading to a calculation of A = 300 N and a derived value for C based on that.
  • Some participants express skepticism about the textbook answers, with one stating that the textbook might be wrong based on their calculations.
  • A later reply acknowledges the difficulty of trusting textbook answers and reflects on a common belief that students are often wrong when their answers differ from those provided in textbooks.

Areas of Agreement / Disagreement

Participants generally do not agree on the correctness of the textbook answers, with multiple competing views on the appropriate values for A and C. The discussion remains unresolved regarding the accuracy of the textbook solutions.

Contextual Notes

Participants express uncertainty about their calculations and the reliability of the textbook answers, indicating a potential dependency on the definitions and assumptions used in their approaches.

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Statics Equilibrium Problem -- 3 Force body in equilibrium

Homework Statement



Q: A T-shaped bracket supports a 150-N load as shown. Determine the reactions at A and C when (a) alpha=90o, (b) alpha =45o

A: (a)A=150N going down, C=167.7N,63.4degrees (b)A= 194.5N going down; C=253N, 77.9 degrees

Here's the diagram from the book:

http://www.glowfoto.com/viewimage.php?img=23-165339L&rand=2124&t=jpg&m=07&y=2010&srv=img6

Homework Equations



sum of forces (it is in equilibrium) and force triangle

The Attempt at a Solution



I made a force triangle where I found the angle 23.565 degrees (which makes sense since they give 63.4 degrees in the textbook). However, using the sine law I expected to come out with the right answer using:


150N/sin(23.565) = A/sin(63.4)

and

150N/sin(23.565) = C/sin(90)​

... instead I keep coming out with A and C values that are double what they should be. Ie. A = 300 N and C = 335.4 N

What am I doing wrong? Am I approaching it the wrong way?

Thanks in advance! :)
 
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Taking moments about C, it is clear that A = 300 and C=sqr(300^2+150^2)
 


Hmmm... that's what I got... however, the answer in the textbook and according to other sources is 150 N [down] for A and 167.7 N [W 63.4 N] for C.
 


Engineers in practice don't have 'answers in the back' for their real problems, and have to find other ways of checking their solutions. That's what you have to do here. I looked at it algebraically and graphically as a check. It wouldn't be the first time that a book was wrong, although I do accept one should have regard to the answer given with a view to discovering whether you have made an awful error. But in this case, I think you are right. Maybe someone else could confirm.
 


I get the same answers you two do. I think the book is probably wrong, based on the problem statement given here.
 


Thanks both of you for your help... I guess I should have more faith!

Whenever I think a textbooks wrong, I think back to one of my first year profs telling the class that usually when a student gets a different answer than the textbook, it's the student who's wrong --not the textbook haha.
 

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