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Statics: Forces in a truss, method of joints
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[QUOTE="yaro99, post: 4456489, member: 479066"] I thought this was the case, but then I went ahead and found F[SUB]AD[/SUB] using joint A, and took a look at joint D to see if I got the same answer for F[SUB]BD[/SUB]. Diagrams: [ATTACH=full]162999[/ATTACH] Joint A: 5 = F[SUB]AD[/SUB]/√5 F[SUB]AD[/SUB] = 20.6 kN This is correct according to the book. Joint D: This one is strange because the ratios don't add up 30/2 ≠ 10/1 At least one of the forces must be wrong, I can't figure it out. [B]EDIT: I realize I forgot to include F[SUB]AD[/SUB] on joint D, going to try that now.[/B] [B]EDIT 2: It seems you're right. I solved joint D with all the forces and got my original answer. Must be a typo, my other answers were "correct" and I haven't had any other inconsistencies with other problems. In any case I'll keep this in mind.[/B] [/QUOTE]
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Statics: Forces in a truss, method of joints
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