A 500N force is applied to the handle at point F. The geometry & measurements are as given in the illustration. Find Cx, Cy, Ax and Ay[/B]
Well, the 500N force produces a 200Nm torque at point D, since DF is 400mm. [/B]
The Attempt at a Solution
So the book's answer key shows a Cx of 4900N and Cy of 19,800N.
Intuitively, I see that the wrench has to grip the pipe and therefore we must have some Cy.
Mathematically, I don't see how the 500N force produces any corresponding vertical reactions. If D is the fulcrum, you wind up with a Cx of 5000N and Cy of zero.
Or, wait: if you want that pipe to turn, shouldn't the fulcrum be dead center of the pipe? Still not seeing how that fulcrum would yield any value for Cy.
Can someone please point me in the right direction?
Thank you in advance.
The Internet is my professor....I'm trying to wade through statics by myself.[/B]
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