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Please click the image to enlarge it

http://img257.imageshack.us/img257/3952/problemfy9.th.jpg [Broken]

I think I have this problem solved correctly, but please check my solution. In the image my problem is *4-24

This is my solution

[tex]M_x\left=-70\cos{60}(0.9)[/tex]

[tex]M_y\left=-70\sin{60}(0.7)[/tex]

which comes out to 73.9 N*M counter clockwise in the Z

For part B

[tex]73.9=Fd[/tex] with d = 0.9

http://img257.imageshack.us/img257/3952/problemfy9.th.jpg [Broken]

I think I have this problem solved correctly, but please check my solution. In the image my problem is *4-24

**The 70-N force acts on the end of the pipe at B Determine (a) The moment of this force about point A, and (B) the magnitude and direction of a horizontal force, applied at C, which produces the same moment take theta = 60 degrees**This is my solution

[tex]M_x\left=-70\cos{60}(0.9)[/tex]

[tex]M_y\left=-70\sin{60}(0.7)[/tex]

which comes out to 73.9 N*M counter clockwise in the Z

For part B

[tex]73.9=Fd[/tex] with d = 0.9

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