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I don't know what i did wrong

Find the tension in the two wires supporting the traffic light

Mass of light= 33 kg

θ of FT1= 53°

θ of FT2=37°

Ʃfx=0

Ft1cos53-ft2cos37=0

ft1cos53=ft2cos37

Ʃfy=mg

ft1sin53-ft2sin37=mg

ft1sin53=mg+ft2sin37

ft1=(ft2sin37+mg)/sin53

ft1=1.33ft2

1.33ft2=(ft2sin37+mg)/sin53

1.33ft2=.72ft2+mg

.61ft2=323.73 N

**Ft2=530.7n**

ft1cos53=ft2cos37

ft1cos53=423.84n

**ft1=704.26n**