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I dont know what i did wrong
Find the tension in the two wires supporting the traffic light
Mass of light= 33 kg
θ of FT1= 53°
θ of FT2=37°
Ʃfx=0
Ft1cos53-ft2cos37=0
ft1cos53=ft2cos37
Ʃfy=mg
ft1sin53-ft2sin37=mg
ft1sin53=mg+ft2sin37
ft1=(ft2sin37+mg)/sin53
ft1=1.33ft2
1.33ft2=(ft2sin37+mg)/sin53
1.33ft2=.72ft2+mg
.61ft2=323.73 N
Ft2=530.7n
ft1cos53=ft2cos37
ft1cos53=423.84n
ft1=704.26n