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hurrfdurrf
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Homework Statement
[PLAIN]http://img15.imageshack.us/img15/7379/unledtzc.png
(The rods are of length L, there is no friction, massless rods, yadee yadee yada)
At a certain angular speed [itex]\omega[/itex], the counterweight performs uniform circular motion. Show that [itex]\omega[/itex] and [itex]\theta[/itex] are related as follows:
[itex]\omega^2 \cos{\theta} = (1 + \frac{2m'}{m}) \frac{g}{L}[/itex]
Homework Equations
[itex]T_1 = L m \omega^2[/itex]
[itex]\cos{\theta} (T_1 - T_2) = g (m + m')[/itex]
The Attempt at a Solution
(Working backwards) Combined above to get
[itex]T_2 \cos{\theta} = m' g[/itex]
which makes a lot of sense, but I'm not sure if the procedure was right
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