Stationary states infinite cubic well

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Homework Help Overview

The discussion revolves around determining the conditions under which a state represented by the operator \( e^{c \cdot L_z} |2,2,2\rangle \) is stationary in the context of an infinite cubic well Hamiltonian. Participants are exploring the relationship between time independence and the parameters involved in the wave function and operators.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are examining the time dependence of the state and attempting to identify values of \( c \) that would lead to a stationary state. There are discussions about the nature of the eigenfunction and eigenvalue, as well as the role of the operator \( L_z \). Some participants question the mathematical validity of the original poster's approach and suggest a review of fundamental concepts.

Discussion Status

The discussion is ongoing, with participants providing insights and questioning the assumptions made about the operators and the nature of stationary states. There is no explicit consensus, but some guidance has been offered regarding the need to clarify the mathematical framework being used.

Contextual Notes

There are indications that participants may be operating under certain assumptions about the definitions and roles of operators in quantum mechanics, which could affect their reasoning. The original poster's approach is noted as potentially naive, suggesting a need for deeper exploration of the underlying principles.

happyparticle
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Homework Statement
For which values of c the state ##e^{c \cdot L_z} |2,2,2>## is stationary for the infinite cubic well Hamiltonian.
Relevant Equations
##\psi (r,t) = \sqrt{\frac{8}{l^3}} sin(\frac{2 \pi x}{l}) sin(\frac{2 \pi u}{l}) sin(\frac{2 \pi z}{l}) e^{-iEt/\hbar}##
##E = \frac{6}{m} (\frac{\pi \hbar}{l})^2##
For a state to be stationary it must be time independent.

Naively, I tried to find the values of c where I don't have any time dependency.

##e^{c \cdot L_z} \psi (r,t) = e^{c L_z} \sqrt{\frac{8}{l^3}} sin(\frac{2 \pi x}{l}) sin(\frac{2 \pi u}{l}) sin(\frac{2 \pi z}{l}) e^{-iEt/\hbar}##

##e^{c \cdot L_z -iEt/\hbar} ##

Thus
##c = \frac{L_z - iEt}{\hbar}##

##c = \frac{L_z - i\frac{6}{m} (\frac{\pi \hbar}{l})^2t}{\hbar}##

I'm wondering if this is correct.

Thanks
 
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happyparticle said:
Homework Statement:: For which values of c the state ##e^{c \cdot L_z} |2,2,2>## is stationary for the infinite cubic well Hamiltonian.
Relevant Equations:: ##\psi (r,t) = \sqrt{\frac{8}{l^3}} sin(\frac{2 \pi x}{l}) sin(\frac{2 \pi u}{l}) sin(\frac{2 \pi z}{l}) e^{-iEt/\hbar}##
##E = \frac{6}{m} (\frac{\pi \hbar}{l})^2##

For a state to be stationary it must be time independent.

Naively, I tried to find the values of c where I don't have any time dependency.

##e^{c \cdot L_z} \psi (r,t) = e^{c L_z} \sqrt{\frac{8}{l^3}} sin(\frac{2 \pi x}{l}) sin(\frac{2 \pi u}{l}) sin(\frac{2 \pi z}{l}) e^{-iEt/\hbar}##

##e^{c \cdot L_z -iEt/\hbar} ##

Thus
##c = \frac{L_z - iEt}{\hbar}##

##c = \frac{L_z - i\frac{6}{m} (\frac{\pi \hbar}{l})^2t}{\hbar}##

I'm wondering if this is correct.

Thanks
A stationary state itself is not time independent. Its absolute square is time independent.
That won't get you very far though. You have to look at something else, I would say.
 
The eigenfunction is ##
\sqrt{\frac{8}{l^3}} sin(\frac{2 \pi x}{l}) sin(\frac{2 \pi u}{l}) sin(\frac{2 \pi z}{l}) e^{-iEt/\hbar}
##
The eigenvalue is ##\frac{12 \hbar^2}{8mL^2}##
Maybe ##e^{c L_z} = e^{\frac{12 \hbar^2}{8mL^2}}##
 
I assume ##L_z## is the operator corresponding to the z-component of orbital angular momentum, so your attempts don't make mathematical sense. You should go back and review the basics of operators and wave functions.

If it's not supposed to represent that operator, what is it supposed to be?
 

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