Stats - find the distribution function of an infinite sample space.

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SUMMARY

The discussion centers on the probability distribution of rolling a die until the first occurrence of a six, specifically the formula P(n) = (5/6)^(n-1) * (1/6). The infinite sample space is defined as Ω = {6, N6, NN6, NNN6, ...}. Participants confirm that the series converges to 1 as N approaches infinity, validating the distribution function. Key feedback includes correcting notation and clarifying the infinite nature of the sample space.

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dtsar
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Homework Statement



A die is rolled until the first time that a six turns up. We shall see that the
probability that this occurs on the nth roll is (5/6)n−1 · (1/6). Using this fact,
describe the appropriate infinite sample space and distribution function for
the experiment of rolling a die until a six turns up for the first time. Verify
that for your distribution function the Ʃ(ω)=1, as ω→∞

Homework Equations



Relevant equations are in the question.

The Attempt at a Solution


Ω = { 6, N6, NN6, NNN6, ... , N...N6 }
Also, I know that the equation is exponential decay, but I just don't know how to get the formula...
I also know that it adds up, because (1/6)+(5/6)(1/6) + (5/6)^2(1/6) .. etc eventually equal to 1 as N→∞
 
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dtsar said:

Homework Statement



A die is rolled until the first time that a six turns up. We shall see that the
probability that this occurs on the nth roll is (5/6)n−1 · (1/6). Using this fact,
describe the appropriate infinite sample space and distribution function for
the experiment of rolling a die until a six turns up for the first time. Verify
that for your distribution function the Ʃ(ω)=1, as ω→∞

Homework Equations



Relevant equations are in the question.


The Attempt at a Solution


Ω = { 6, N6, NN6, NNN6, ... , N...N6 }
Also, I know that the equation is exponential decay, but I just don't know how to get the formula...
I also know that it adds up, because (1/6)+(5/6)(1/6) + (5/6)^2(1/6) .. etc eventually equal to 1 as N→∞

(i) What you wrote was (5/6)n-1 - 1.(1/6), which means (5n/6) - (1/6). You should have written either (5/6)^(n-1) - (1/6) or used the "S U P" button to get (5/6)n-1 - (1/6).
(ii) Saying Ʃ(ω)=1, as ω→∞ makes no sense: the ω need not be numbers, so they can't "go to infinity". Just saying Ʃ(ω)=1 is enough.
(iii) You write Ω as though it has an "end", but it doesn't just write Ω = {6, N6, NN6, NNN6, ... }. Also, if you use N here you should not later say "as N → ∞". Use a different symbol.

Aside from these writing issues, I don't see your problem; you seem to have answered the questions you were asked. For example, when you say "I just don't know how to get the formula...", that is not relevant: you are *given* the formula, and are asked to use it. You have done that correctly.

RGV
 

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