Stefan-Boltzmann's Law. How to apply to the Sun

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Homework Help Overview

The discussion revolves around applying Stefan-Boltzmann's Law to calculate the radius of the Sun, using given values for temperature and luminosity. Participants are exploring the relationship between these variables and the resulting calculations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to apply the Stefan-Boltzmann equation to derive the Sun's radius. There are questions about the accuracy of calculations and the interpretation of results, with some expressing confusion over discrepancies between expected and calculated values.

Discussion Status

The discussion is ongoing, with participants sharing their calculations and questioning the accuracy of their results. Some have noted that their results align closely with known values from NASA, while others are seeking clarification on their methods and assumptions.

Contextual Notes

There are indications of potential miscalculations regarding units, with one participant mentioning a possible confusion between kilometers and meters. Participants are also reflecting on the accuracy of their results in relation to established data.

PMNIMG
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Homework Statement
Use the Stefan-Boltzmann's Law and calculate Sun's radius.
T☉=5772K
L☉= 3.828×10^(26) W
Relevant Equations
E=σT^4
L=4πr^2*σT^4
r=(L/4π*σT^4)^(1/2)
r^2=(3.828*10^(26))/(4π*σ(5772)^4)
It's diffrent from what I know...
 
Last edited:
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PMNIMG said:
Homework Statement: Use the Stefan-Boltzmann's Law and calculate Sun's radius.
T☉=5772K
L☉= 3.828×10^(26) W
Relevant Equations: E=σT^4
L=4πr^2*σT^4
r=(L/4π*σT^4)^(1/2)

r=(3.828*10^(26))/(4π*σ(5772)^4)
It's diffrent from what I know...
Did you mean ##r^2=…##?
Other than that, what is stopping you?
 
haruspex said:
Did you mean ##r^2=…##?
Other than that, what is stopping you?
Oh, sorry. I modified it now.
From what I know, the radius of the sun is 696340000m. It is diffrent from the solution...
And I don't know what seems to be the problem.
 
According to NASA, the suns diameter is 695,700,000 meters, which according to your maths is accurate to 4 decimal places. So I also don't know what the problem is, as there doesn't appear to be one. Even the number you display as the given radius is off by less than 1/10 of 1 percent.
 
can you show me how to calculate?
I think it's diffrent from mine...
 
PMNIMG said:
can you show me how to calculate?
I think it's diffrent from mine...
@OmCheeto did not (I think) do any calculation other than to find the % difference.
Your result agrees pretty well with NASA's. What is the given solution?
 
Oh, I think I miscalculated...
sorry I disturbed you all with dumb question...
I think I put km instead of m...
 
PMNIMG said:
Oh, I think I miscalculated...
sorry I disturbed you all with dumb question...
I think I put km instead of m...
No problem.
 
I do that sometimes...
If you can't find anything odd about my qusetion, please tell me reason!
sorry
 

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