Stirling's Approximation Problem

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Stirling's approximation can be applied to evaluate the gamma function, Γ(N), where Γ(n) = (n-1)! is valid for positive integers. For Γ(12.3), the approximation can be calculated using Stirling's formula by substituting (12.3 - 1) = 11.3. The formula also applies to non-integer values, allowing for the evaluation of (π^2)! and (1/2)! by appropriately adjusting the inputs. It's important to understand the context and conditions of the gamma function to ensure accurate calculations. Proper application of Stirling's approximation requires careful consideration of the values being used.
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Homework Statement


Use Stirling's Approximation formula to evaluate the following:
1) Γ(12.3) where Γ(N) is the gamma function
2) (π^2)! This is suppose to be pi squared
3) (1/2)!



Homework Equations


So here is Stirling's approximation formula:

N! ~= sqrt(2πN)(N/e)^N (where ~= means approximately equal to). And this is accurate to at least two decimal places for N >= 9.



The Attempt at a Solution


For the first problem I am unsure about what to do. I found a formula that says Γ(n) = (n-1)! but I'm not sure if this is only valid for integers. Can I simply plug into stirling's approximation formula (n-1) or in this case (12.3 - 1) = 11.3 to obtain the approximation for Γ(12.3)? For the other two problems do I simply plug in pi^2 and (1/2) into the formula? I apologize if this seems overly simple but this my first time ever seeing this formula and want to make sure I know how to use it in general. Thank you very much to anyone who can help.
 
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I found a formula that says Γ(n) = (n-1)! but I'm not sure if this is only valid for integers.
That version is only valid for positive integers.

The Gamma function is more broadly defined for complex numbers other than non-positive integers.

Once you have the Stirling approximation to the gamma function, you can use it to evaluate the rest... it's not just a matter of blindly plugging the number into the equation, you have to make the number the right kind to fit.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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