Stoichiometry again (using solutions)

[Attraction]

Homework Statement

H2SO4 + Na2CO3 g Na2SO4 + H2O + CO2

Calculate the molarity of the H2SO4 solution if it takes 40.0 mL of H2SO4 to neutralize 46.7 mL of a 0.364 M Na2CO3 solution.

The Attempt at a Solution

The equation is balanced. My plan was

grams Na2CO3 --> mols Na2CO3--> molsH2SO4---> mols/litre H2SO4(equals Molarity).


my calculations...

.364gramsNa2CO3 x 1molNa2CO3/106gramsNa2CO3 x 1molH2SO4/1molNa2CO3 x 1000mlH2SO4/1LH2SO4

I know I am going wrong with the last bit but can't think of any other way to do it.

Help!?

 

[symbolipoint]

At least you recognized the 1:1 mole ration between the acid and the carbonate.

moles Na₂CO₃=(0.467L)(0.364M)=moles of H₂SO₄.

Can you finish the rest? You used 40 mililiters of unknown concentration sulfuric acid.

 

[Attraction]

I don't know how, but I copied the wrong question here in this thread. I started with grams but there is no grams in the question. The question I was supposed to copy was this one...

1. Homework Statement

Given the following equation:

H2SO4 + Na2CO3 ----> Na2SO4 + H2O + CO2

Calculate the molarity of the H2SO4 solution if it takes 40.0 mL of H2SO4 to neutralize 0.364 g of Na2CO3.

So my attempt at a solution is still the same. Sorry about that, I don't know how that happened but I should have rechecked before posting.

Anyway, with this new question, where we are given grams, is my method a bit closer to correct or not? I am having difficulty with the end, converting to moles/litre.



My answer was...
The equation is balanced. My plan was

grams Na2CO3 --> mols Na2CO3--> molsH2SO4---> mols/litre H2SO4(equals Molarity).


my calculations...

.364gramsNa2CO3 x 1molNa2CO3/106gramsNa2CO3 x 1molH2SO4/1molNa2CO3 x 1000mlH2SO4/1LH2SO4

I know I am going wrong with the last bit but can't think of any other way to do it.

Help!?

 

[Bohrok]

Calculate the moles of H₂SO₄ that you have, right before the last part of your calculation. Since molarity = moles/liters, divide the moles of H₂SO₄ by 40.0mL in liters.

 

[Attraction]

perfect, thanks man. I understand fully now.