How Do You Modify the Stoichiometry for Sulfur-Included Food Waste Degradation?

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SUMMARY

The discussion focuses on modifying the stoichiometric equation for the anaerobic degradation of sulfur-included food waste to methane. The general formula for food waste degradation is presented as CnHaObNc + (n - a/4 - b/2 + 3c/4)H2O → (n/2 + a/8 - b/4 - 3c/8)CH4 + (n/2 - a/8 + b/4 + 3c/8)CO2 + cNH3. The inclusion of sulfur modifies the equation to CnHaObNcSd, necessitating an atom balance for hydrogen, carbon, and oxygen to derive coefficients for H2O, CH4, and CO2. The solution involves setting up three linear algebraic equations based on these balances.

PREREQUISITES
  • Understanding of stoichiometry in chemical reactions
  • Familiarity with anaerobic digestion processes
  • Basic knowledge of linear algebra for solving equations
  • Concept of atom balance in chemical equations
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  • Study the stoichiometric coefficients in chemical reactions
  • Learn about the role of sulfur in anaerobic digestion
  • Explore linear algebra techniques for solving systems of equations
  • Research the impact of food waste composition on methane production
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Environmental scientists, chemical engineers, and researchers involved in waste management and anaerobic digestion processes will benefit from this discussion.

gfd43tg
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Homework Statement


There's no problem statement, I'm doing this as part of my project

For degradation of food wastes to methane, the general formula is given for food waste (without sulfur)

##C_{n}H_{a}O_{b}N_{c} + (n - \frac {a}{4} - \frac {b}{2} + \frac {3c}{4})H_{2}O \rightarrow (\frac {n}{2} + \frac {a}{8} - \frac {b}{4} - \frac {3c}{8})CH_{4} + (\frac {n}{2} - \frac {a}{8} + \frac {b}{4} + \frac {3c}{8})CO_{2} + cNH_{3}##

However, for my purpose I need to include sulfur, so my formula should be
##C_{n}H_{a}O_{b}N_{c}S_{d}##

Homework Equations

The Attempt at a Solution


This part with the N and S are easy, but figuring out the other stuff is of course my issue.
##C_{n}H_{a}O_{b}N_{c}S_{d} + (...)H_{2}O \rightarrow (...) CH_{4} + (...)CO_{2} + cNH_{3} + dH_{2}S##
 
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CH4 and CO2 don't change.

Can't say whole equation makes much sense to me, it looks rather arbitrary.
 
I imagine they would change, since you are using hydrogen to make H2S instead of going into CH4, right? This is a pseudo reaction of course, I'm trying to model solid wastes to methane from anaerobic digestion without having to model all the many reactions involved in a real digestion
 
OK, you are right, they are not independent.
 
What you do is call x the coefficient of H2O, y the coefficient of CH4, and z the coefficient of CO2. Then you do an atom balance on H, C, and O. This gives you three linear algebraic equations in the three unknowns x, y, and z. Just solve for these unknowns.

Chet
 
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Chestermiller said:
What you do is call x the coefficient of H2O, y the coefficient of CH4, and z the coefficient of CO2. Then you do an atom balance on H, C, and O. This gives you three linear algebraic equations in the three unknowns x, y, and z. Just solve for these unknowns.

Chet
Thanks, now time to crank out the algebra
 

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