Stoichiometry question in chemistry

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SUMMARY

The discussion revolves around a stoichiometry problem involving the reaction of sulfur dioxide (SO₂) with oxygen (O₂) to form sulfur trioxide (SO₃). The balanced chemical equation is 2SO₂(g) + O₂ → 2SO₃(g). Given 10.0 dm³ of SO₂ and 6.0 dm³ of O₂, the volume of SO₃ produced can be determined using the stoichiometric ratios from the equation. The correct answer is 15.0 dm³ of SO₃, as the limiting reactant is O₂.

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WMDhamnekar
MHB
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Hi,
10.0 dm³ of sulfur dioxide is reacted with 6.0 dm³ of oxygen according to equation below.
2SO₂(g) + O₂ → 2SO₃(g)

What volume of sulfur trioxide in dm³ is formed?

If any member knows the correct answer to this question may answer to this question.

Please answer with your workings.
 
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Hi Dhamnekar,

That looks identical to https://mathhelpboards.com/threads/question-on-stoichiometry.27814/.
 
Klaas van Aarsen said:
Hi Dhamnekar,

That looks identical to https://mathhelpboards.com/threads/question-on-stoichiometry.27814/.
Hello,
Oh, I am very sorry. I asked the same question again.
 

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