1. The problem statement, all variables and given/known data A stone is thrown from a bridge with an initial vertical velocity of magnitude 4.0m/s/ Determine the stone's velocity after 2.2s if the direction of the initial velocity is (a) upward, and (b) downward. Neglect air resistance. 2. Relevant equations Aav=Vf - Vi / Δt Vi + Aav(Δt) = Vf 3. The attempt at a solution b) 2.6 x 101m/s Easy to find as you enter in the given information into the formula. (a) on the other hand I have difficulty understanding. I attempted the problem, with this formula (-Vi) + Aav(Δt) = Vf. The answer I got corresponds to the answer in text, but I don't really understand how that works. I'd like to know for similar problems in the future.