Stopping a battery from shorting (while driving a magnetic coil)

Click For Summary
SUMMARY

The discussion focuses on optimizing the design of an electromagnet powered by a 1.5V DC battery to prevent battery drain and shorting. Key insights include the importance of calculating the required current and the use of thinner gauge wire with more turns to enhance efficiency. Adding a resistor is deemed ineffective as it wastes power, while using a DC-DC converter can provide a more efficient voltage transformation. Participants emphasize the significance of understanding battery ratings and the relationship between ampere-turns and magnetic field strength.

PREREQUISITES
  • Understanding of electromagnet design principles
  • Knowledge of wire gauge and resistance (AWG)
  • Familiarity with battery ratings and specifications
  • Basic electrical circuit analysis skills
NEXT STEPS
  • Research "DC-DC converter applications for electromagnets"
  • Learn about "AWG wire resistance calculations"
  • Study "battery capacity and discharge rates"
  • Explore "ampere-turns and their effect on magnetic fields"
USEFUL FOR

Electronics hobbyists, engineers designing electromagnets, and anyone interested in optimizing battery-powered devices for efficiency.

burntoastt
Messages
5
Reaction score
1
Can anyone tell me how to determine the minimum resistance a battery needs to stop it from shorting? for example I'm making an electro magnet, with a 1.5v dc battery cell, but when i turn it on it just drains the battery.
 
Physics news on Phys.org
burntoastt said:
Can anyone tell me how to determine the minimum resistance a battery needs to stop it from shorting? for example I'm making an electro magnet, with a 1.5v dc battery cell, but when i turn it on it just drains the battery.
An electromagnet amounts to an inductor. An DC current through an inductor amounts to a short circuit. Any resistor will prevent it from being a "short circuit".

However, that's not the relevant question. The relevant questions are how much current you want, how much time you want it for and how much charge you have to expend.

Edit: I am no expert on electromagnet design, but it seems to me that any power dissipated in a resistor is completely wasted. If you are draining power too quickly, the answer is not to add a resistor. It is to use a thinner gauge wire and add more turns.
 
Last edited:
  • Like
Likes   Reactions: Merlin3189 and berkeman
It's not a matter of shorting as much as it is the current requirements of your electromagnet. Start by considering how much current you need for your application. Then you need to consider the rating of the battery you plan to use. Read about battery ratings here https://www.allaboutcircuits.com/textbook/direct-current/chpt-11/battery-ratings/. Then calculate how long your battery will last. In short, the battery has a limited amount of charge (Amp##\cdot##hr rating) it can provide. Once the charge is gone, it's gone. You can prolong battery life by reducing the current in the electromagnet, but that will of course reduce the magnetic field.
 
  • Like
Likes   Reactions: berkeman
jbriggs444 said:
it seems to me that any power dissipated in a resistor is completely wasted. If you are draining power too quickly, the answer is not to add a resistor. It is to use a thinner gauge wire and add more turns.
+1.0

You either figure out how much wire you need to give you the resistance (and therefore the current) that you want, or you put a DC-DC converter between your power source and your coil to have an efficient way of transforming the source voltage down.

You can find out the resistance per length for different AWG wires using Wire Tables, like the one on this page:

https://www.powerstream.com/Wire_Size.htm

:smile:
 
The pull of an electromagnet is a function of ampere-turns (and other variables). That's total current times number of turns. One thousand turns at one ampere will pull the same as ten turns at one hundred amperes.

Connect a voltmeter to your battery. Then connect your electromagnet, and observe the voltage drop. If the voltage drops a lot, most of the energy is wasted heating the battery, and you need more turns. If you run out of room to add more turns, use smaller wire. As a very rough guess, for an electromagnet driven by a 1.5 volt battery, you will end up with 30 gauge wire or a little smaller. That assumes enamel covered wire, not wire with thick rubber or plastic insulation.
 
  • Like
Likes   Reactions: berkeman
burntoastt said:
I'm making an electro magnet, with a 1.5v dc battery cell, but when i turn it on it just drains the battery.

Before you put too much effort on doing it better, it is a good time to think about what you are trying to accomplish. How do you define success in your project? Can you share that with us.
 
  • Like
Likes   Reactions: Nugatory
jbriggs444 said:
Edit: I am no expert on electromagnet design, but it seems to me that any power dissipated in a resistor is completely wasted. If you are draining power too quickly, the answer is not to add a resistor. It is to use a thinner gauge wire and add more turns.
Any power lost through resistance in the wire is also wasted. The strength of the magnetic field just depends on the current and the number of turns. You probably need to limit the current to keep the battery from (literally) blowing up, but it doesn't really matter if the power is dissipated in a resistor element or the wire itself, as long as the series resistance is the same, and as long as the resistor and wire don't overheat.

The main benefit of a thinner gauge wire is that you can fit more turns in, so you can get the same magnetic field with less drain on the battery.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 42 ·
2
Replies
42
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 43 ·
2
Replies
43
Views
7K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K