Stopping Distance + Reaction Time Problem -> Physics beginner

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SUMMARY

The discussion focuses on calculating the stopping distance of a car traveling at 80 km/h with a reaction time of 0.5 seconds and a deceleration of 8 m/s². The initial speed is converted to 22.22 m/s, leading to a pre-braking distance of 11.11 m. After applying the kinematic equations, the total stopping distance is determined to be 41.97 m. The participant confirms the correctness of their calculations and receives additional resources for further learning.

PREREQUISITES
  • Understanding of kinematic equations, specifically V1 = V0 + at and D = V0t + 1/2at²
  • Basic knowledge of unit conversions, particularly from km/h to m/s
  • Familiarity with concepts of acceleration and deceleration
  • Ability to perform algebraic manipulations to solve for unknowns
NEXT STEPS
  • Study the kinematic equation that relates velocity and distance directly for accelerated motion
  • Practice converting speeds from km/h to m/s for various scenarios
  • Explore additional examples of stopping distance calculations in physics
  • Learn about the implications of reaction time on stopping distances in real-world driving scenarios
USEFUL FOR

This discussion is beneficial for physics students, particularly beginners, as well as educators looking for examples of kinematic equations in action. It also aids anyone interested in understanding the practical applications of physics in driving safety.

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Stopping Distance + Reaction Time Problem ---> Physics beginner

Homework Statement


A car is traveling at 80km/h, and brakes with a reaction time of .5 seconds. The car decelerates at 8m/s/s, determine the stopping distance of the car.


Homework Equations



- V1 = V0 + at
- D = V0t + 1/2at2

Where:
V1 = Final Speed
V0 = Initial Speed
A = Acceleration
T = Time
D = Distance

The Attempt at a Solution



Distance Traveled before Braking:
80km/h = 22.22m/s

0.5 * 22.22m/s = 11.11 m

Distance After Reaction:
V1 = V0 + at
0 = 22.22 - 8t
t = 2.7775 seconds

D = V0t + 1/2at2
D = 22.22 * 2.7775 - [(8 * 2.77752)/2]
D = 30.86m

Total Stopping Distance = 11.11m + 30.86m
= 41.97 m

Notes
I am only beginning to learn some basic concepts of physics in class, so I'm not entirely sure about the equations.

My teacher has provided no answer sheet to the question, and I am finding it hard to grasp the method of solving the question without a step by step example from a similar question.

I'd greatly appreciate it if anyone could let me know if I am right, or how to do it if I am wrong.

Thanks :D
 
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Thank you for the help and additional formulas !
Now I'll be able to do my other sums :D
 
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