String wraped around the cylinder, friction?

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SUMMARY

The discussion centers on determining the force of friction acting on a cylinder with mass m and radius R when a string wrapped around it is pulled with a constant force F. The participants conclude that the cylinder will roll in the opposite direction of the pulling force, resulting in friction acting in the direction of the pull. The relationship between friction, angular velocity, and angular acceleration is explored, emphasizing that friction is influenced by the cylinder's rotation and the moment of force generated.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with rotational dynamics and moment of inertia
  • Knowledge of angular acceleration and its relationship to linear acceleration
  • Basic concepts of friction and its role in motion
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  • Study the relationship between linear and angular motion in physics
  • Learn about the equations of motion for rolling objects
  • Investigate the principles of static and kinetic friction
  • Explore the concept of torque and its application in rotational dynamics
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Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators seeking to clarify concepts related to friction and rotational motion.

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Homework Statement


we have a cylinder, mass m, radius R. a string is wrapped around the cylinder. and it is all located on the horizontal surface, and when we pull the string, the cylinder starts to roll.
if we pull the string with the constant force F, determine the force of friction (direction and number=mangitude?)


Homework Equations



?

The Attempt at a Solution



well I think that it will start to roll backwards (opposite to the direction of pulling); and so the friction will be in the direciton of pulling. if the force is constant the acceleration is constant. by pulling the string we rotate the cylinder. I don't know how this rotation relates to friction. Is the force of friction proportional to the angular velocity of the cylinder? ie. proportinal to the angular acceleration? ie. the faster we pull the string the faster the cylinder rotates and the friction is bigger. if the cylinder rotates then it has moment of force M=I*alpha, and it is equal to he sum of the moment of force of friction and mom. of force due to deformation of the surface and the body (it says something like that in my book?)

so, can anybody help me, please I and my colleagues are desperate. I must admit that I haven't learned the theory yet, but I will soon, and then I will see that some of things I just wrote don't make sense and that I must have appeared to be an idiot for not knowing how to solve something as simple as this, but till then, can anybody clarify this problem?
tnx in advance
 
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Hi ldv! :smile:

Hint: start by finding the angular acceleration. :wink:
 

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