Strong Equivalence Principle Question

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SUMMARY

The discussion centers on the strong equivalence principle and its implications for gravitational blue shift observed in photons. The user describes a scenario where a photon emitted from a high altitude appears to have a higher frequency when observed at a lower altitude, indicating gravitational blue shift. The formula for gravitational Doppler effect, νobs = νsource √((1-β)/(1+β)), where β = v/c, is introduced to analyze the situation. The confusion arises from the interpretation of acceleration in a laboratory setting, emphasizing that to emulate Earth's gravity, the floor must accelerate upwards, not downwards.

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  • Understanding of the strong equivalence principle in General Relativity.
  • Familiarity with gravitational blue shift and red shift concepts.
  • Knowledge of the gravitational Doppler effect and its mathematical representation.
  • Basic comprehension of the relationship between velocity (v) and the speed of light (c).
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  • Study the implications of the strong equivalence principle in different gravitational fields.
  • Learn about the mathematical derivation of the gravitational Doppler effect.
  • Explore the concept of gravitational blue shift in various astrophysical contexts.
  • Investigate the role of acceleration in General Relativity and its effects on light propagation.
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Students and enthusiasts of General Relativity, physicists exploring gravitational phenomena, and anyone interested in the implications of the strong equivalence principle on light behavior in gravitational fields.

latentcorpse
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My notes say that a photon traveling from a high altitude to an observer at low altitude appears to have a higher frequency i.e. gravitational blue shift.

now I am having trouble getting this:

the strong equivalence principle says we can substitute this "laboratory" with a laboratory that is undergoing uniform acceleration -g in deep space.

i then drew a box with the photon being emitted from the roof and traveling towards the floor. the box is moving downward with an acceleration g. so as we are moving away from the source we should use the following formula for gravitational doppler effect:

\nu^{obs}=\nu^{source} \sqrt{\frac{1-\beta}{1+\beta}} where \beta=\frac{v}{c} which predicts a gravitational redshift as \beta is positive as we are moving away from the source with velocity v. I'm messing up somewhere but i can't see it.

help!
 
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latentcorpse said:
... a photon traveling from a high altitude to an observer at low altitude ...
... substitute ... with a laboratory that is undergoing uniform acceleration -g in deep space.
... photon ... emitted from the roof and traveling towards the floor. the box is moving downward with an acceleration g.
... we are moving away from the source ...
In order to emulate Earth's gravity, so that things fall to the floor, the floor should accelerate upwards, not downwards. We are "moving" toward the source (if we are on the floor).

latentcorpse said:
\nu^{obs}=\nu^{source} \sqrt{\frac{1-\beta}{1+\beta}} where \beta=\frac{v}{c}
How are you going to determine β?
 
ok. i think what was confusing me was that whilst gravitation on Earth is -\vec{g} downward. the strong equivalence principle equivalent of this will be a laboratory in deep space which is accelerating "up" with magnitude g, correct?

this would certainly explain why we observe a gravitational blue shift...

its just an introguction course to GR so we were just examining whether <br /> \beta was positive or negative and noting if we see blue shift or red shift as a result...
 

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