Strong Law of large numbers question.

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The discussion centers on the Strong Law of Large Numbers (SLLN) and its application to sequences of independent random variables. The user questions whether the failure of SLLN for a sequence X[n] implies its failure for the sequence Y[n] defined as Y[n] = max(X[n], X[n+1]). The user proposes that if the expectation E(|X[n]|) is bounded by 5, the same condition should hold for Y[n]. The conversation highlights the need to demonstrate that the probability P(|(ΣY[i]/n) - (ΣE(Y[i])/n)| < ε) does not converge to 1, paralleling the behavior of X[n].

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I have this question which I am puzzled from, hope someone can help me here.

Prove/disprove:
If X[n] is a sequence of independent random variables, s.t for each n E(|X[n]|)<5 (E is the expecatation value) and the stong law doesn't apply to this sequence, then the same law doesn't apply on the sequence [tex]Y_n=max(X_n,X_{n+1})[/tex].

Any tips on how to solve this question, I think the assertion is correct, not sure how to show it though, I mean: [tex]P(|\frac{\sum_{i=0}^{n}X_i}{n}-\frac{\sum_{i=0}^{n}E(X_i)}{n}|>=\epsilon)[/tex] doesn't converge to zero as n approaches infinity, so I need to show that the same also applies to Y[n], or to show that its complement doesn't converge to 1.

So, [tex]P((|\frac{\sum_{i=0}^{n}Y_i}{n}-\frac{\sum_{i=0}^{n}E(Y_i)}{n}|<\epsilon)>=1-\frac{Var(Y_n)}{n^2\epsilon^2}[/tex].
Now [tex]Var(Y_n)=E(Y^2_n )-E(Y_n)^2[/tex], now here I need to use that E(|X[n]|)<5, but not sure how.
 
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