Strontium Chloride + Copper (II) Sulphate Pentahydrate -> ?

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SUMMARY

The reaction between Strontium Chloride (SrCl2) and Copper (II) Sulphate Pentahydrate (CuSO4·5H2O) results in the formation of Strontium Sulphate (SrSO4) as a white precipitate and Copper (II) Chloride (CuCl2) remaining in solution, which gives a blue color. In a lab experiment, 2.00g samples of each salt were dissolved in water, mixed, and filtered, yielding a white powder and a blue liquid. The initial hypothesis of the products was corrected based on the observed results, confirming the chemical equation: SrCl2 + CuSO4 → SrSO4 + CuCl2.

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  • Understanding of basic chemical reactions and precipitate formation.
  • Familiarity with solubility rules and ionic compounds.
  • Knowledge of laboratory techniques such as filtration and crystallization.
  • Basic skills in stoichiometry and chemical equations.
NEXT STEPS
  • Research the properties and applications of Strontium Sulphate (SrSO4).
  • Learn about the solubility of Copper (II) Chloride (CuCl2) in various solvents.
  • Investigate the process of crystallization and factors affecting precipitate formation.
  • Explore the role of hydration in Copper (II) Sulphate Pentahydrate (CuSO4·5H2O) and its behavior in reactions.
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Strontium Chloride + Copper (II) Sulphate Pentahydrate --> ?

Well, I did a lab in class a few days ago, where we were to react Strontium Chloride with Copper (II) Sulphate Pentahydrate, and determine what the precipitate formed was.

Here's how the lab worked. We took 2.00g samples of each salt, and dissolved them in about 10ml of water, then mixed the dissolved salts together, once the reaction occurred, the precipitate and the liquid were poured into a funnel lined with filter paper, the blue liquid trickled down into a beaker underneath, and the precipitate stayed on the filter paper. Once the draining was finished, the filter paper with the precipitate was allowed to dry out for a day. A white powder was formed. Forgot to add in that before the precipitate and liquid were drained, extra water was added to dissolve any excess crystals in the solution.

My problem is, I don't know what the powder is, or the blue liquid that drained out was. Initially I predicted the products to be Copper (II) Chloride, Strontium Sulphate, and Water, but I realized it didn't make sense, seeing as the precipitate wasn't a clear crystal, and none of my predicted products formed a blue liquid. Can someone help me?

EDIT: Noticed I posted this in the wrong forum, my apologies, perhaps someone could move it to the correct area.

Joe
 
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Joe.Z said:
Well, I did a lab in class a few days ago, where we were to react Strontium Chloride with Copper (II) Sulphate Pentahydrate, and determine what the precipitate formed was.

Here's how the lab worked. We took 2.00g samples of each salt, and dissolved them in about 10ml of water, then mixed the dissolved salts together, once the reaction occurred, the precipitate and the liquid were poured into a funnel lined with filter paper, the blue liquid trickled down into a beaker underneath, and the precipitate stayed on the filter paper. Once the draining was finished, the filter paper with the precipitate was allowed to dry out for a day. A white powder was formed. Forgot to add in that before the precipitate and liquid were drained, extra water was added to dissolve any excess crystals in the solution.

My problem is, I don't know what the powder is, or the blue liquid that drained out was. Initially I predicted the products to be Copper (II) Chloride, Strontium Sulphate, and Water, but I realized it didn't make sense, seeing as the precipitate wasn't a clear crystal, and none of my predicted products formed a blue liquid. Can someone help me?

EDIT: Noticed I posted this in the wrong forum, my apologies, perhaps someone could move it to the correct area.

Joe

Sr(Cl)2 + CuSO4 --> SrSO4 + Cu(Cl)2

SrSO4 precipitates in white crystals;
Cu(Cl)2 stays dissolved in water forming a bluish solution.
 

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