Structure R^k and midpoints of vectors

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SUMMARY

The discussion revolves around problem 16 from Rudin's "Principles of Mathematical Analysis," focusing on the existence of points z in R^k based on the distance d between points x and y. The conclusions drawn are: (a) If 2r > d, there are infinitely many points z satisfying norm[z-y] = norm[z-x] = r; (b) If 2r = d, there is exactly one point z; (c) If 2r < d, no such points z exist. The Euclidean norm is defined as the square root of the sum of squares of components, and the geometric interpretation involves a circle in the tangent plane at the midpoint of x and y.

PREREQUISITES
  • Understanding of Euclidean space R^k
  • Familiarity with norms, specifically the Euclidean norm
  • Knowledge of geometric interpretations in higher dimensions
  • Proficiency in mathematical proofs, particularly using the triangle inequality
NEXT STEPS
  • Study the geometric properties of circles in higher dimensions
  • Learn about constructive proofs in mathematical analysis
  • Review the triangle inequality and its applications in proofs
  • Explore additional problems in Rudin's "Principles of Mathematical Analysis" for further practice
USEFUL FOR

This discussion is beneficial for mathematics students, particularly those studying analysis, as well as educators seeking to understand the complexities of geometric interpretations in higher-dimensional spaces.

SiddharthM
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First this is NOT a homework problem. I am undertaking a self-study of mathematical analysis by following Rudin's Principles of Mathematical analysis. I have done a course in analysis before but this is a high-powered review of sorts.

So I'm currently on the first chapter's problem set and I've gotten stuck on problem 16, which asks:

Let x,y in R^k, k>/=3 (at least 3-space), norm[x-y] = d>0 prove:

a)If 2r>d There are infinitely many z in R^k s.t. norm[z-y]=norm[z-x]=r
b)If 2r=d there is exactly one such z.
c)If 2r<d there are no such z.

That is the question as stated, to clarify the norm I speak of is the tradition euclidean k-space norm (i.e. root of sum of squares of components).

Part a) is the one I've made the least progress on, b) I'm half done and c) is a simple proof by contradiction using the triangle inequality.

Geometrically (for part a)) consider the line between x and y, there is a perpindicular plane at the midpoint (x+y)/2 (perpendicular to the line connecting x and y) and the set of infinite z that a) asks for is the circle of radius (r^2 - (d/2)^2)^(1/2) which is nonzero b/c of the hypothesis lying on the tangent plane centered at the midpoint (x+y)/2. The thing is, I presume rudin wants me to construct a general z that admits infinitely vectors, but I've found this very difficult to do using the definitions and theorems given in the chapter. Any ideas?

Part b) the only such z is x+y=2 but I can't for the life of me prove that it is the ONLY solution with rigour.

Help would be much appreciated.

Cheers,
Siddharth M.

PS: obviously the problem I'm having is providing a clean and neat proof strictly using definitions and theorems as is required of an analyst but such a solution has thus far escaped me.
 
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as you know, my advice is to choose some more user friendly book, especially for self study.

have you drawn a picture in the plane? i.e. for the forbidden k = 2 case?
 
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It's not so much self-study as much as it is a high-powered review. I'm familiar with the theorems in the first 7 chapters, also I've taken a course in measure theory that was significantly more challenging. That being said Rudin is perfect for honing my problem-solving skills while reviewing the essential theorems of the theory.

I've "drawn" it in 3-space - it's actually fairly easy to picture.

in the plane the assertions are the same except 2r>d means there are two solutions, on the line you never get a solution unless 2r=d, in which case only the midpoint suffices.

The only way I can see to do this is using a constructive proof, but my methods have gotten too messy. There needs to be a slicker way of going about this theorem.
 

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