Struggling to Find X(t) Using Inverse Laplace Transform

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schapman22
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Homework Statement



Having found the laplace transform of a differential equation. I must now find X(t). All of my work is attached. The problem I am having is fitting my function of s to my table of transforms. I tried using partial fractions but it took me in a loop.

The Attempt at a Solution



I attached everything.
 
Attachments
  • Handwritten Laplace transform working, rotated sideways: the ODE y'' - 2y' + x, transforms of the derivatives, leading to Y(s) = X(s)(s^2 - 2s + 1), then X(s)/Y(s) = 1/(s^2 - 2s + 1) boxed.
    homework3.jpg
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  • Handwritten partial fraction decomposition of 1/(s-1)^2 as A/(s-1) + B/(s-1)^2, with A and B solved by substituting s = 2 and s = 3, giving A = 0 and B = 1, and a blank box labelled x(t).
    homework5.jpg
    16.6 KB · Views: 387
I know the answer is et which means somehow 1/(s-1)2 becomes 1/(s-1). But I don't understand how to get rid of the other (s-1) in the denominator.
 
Hey I still can't figure this one out. If anyone has any advice it would be very much appreciated. Thank you.
 
I have trouble reading your images, but if you are trying to inverse ##\frac 1 {(s-1)^2}## you can use one of the shifting theorems$$
\mathcal L^{-1}f(s-a) = e^{at}\mathcal L^{-1}f(s)$$Do you see how to use that? Your answer isn't just ##e^t##.