Find the inverse laplace transform of this function

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SUMMARY

The inverse Laplace transform of the function F(s) = 3/(s(s^2 + 2s + 5)) can be computed using partial fraction decomposition. The decomposition yields F(s) = (3/5)s - (3/5)((s+2)/((s+1)^2 + 4)). To find the inverse Laplace transform of the second term, it is essential to express (s+2) as (s+1) + 1, allowing the application of standard inverse Laplace transform formulas. This method effectively simplifies the problem and leads to the correct solution.

PREREQUISITES
  • Understanding of Laplace transforms and their properties.
  • Familiarity with partial fraction decomposition techniques.
  • Knowledge of completing the square in algebra.
  • Experience with inverse Laplace transform tables and formulas.
NEXT STEPS
  • Study the application of partial fraction decomposition in Laplace transforms.
  • Learn about completing the square for quadratic expressions.
  • Review inverse Laplace transform tables for common functions.
  • Practice solving inverse Laplace transform problems with varying complexity.
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Students studying differential equations, engineers working with control systems, and anyone seeking to master inverse Laplace transforms in mathematical analysis.

mingming
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Homework Statement


F(s) = 3/(s(s^2 +2s + 5))


Homework Equations





The Attempt at a Solution


I have used partial fraction using coefficients.

F(s) = (3/5)s - (3/5) ((s+2)/(s^2 +2s + 5))
and reduce s^2 +2s +5 by completing the square
F(s) = (3/5)s - (3/5) ((s+2)/((s+1)^2 + 4))
I am having trouble finding the right inverse laplace for the second term since (s+2) must be equal to (s+1) to apply the inverse laplace formula in the table...what should i do ...
 
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Use the fact that s+2 = (s+1)+1 and break that term into two terms.
 

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