A moving particle encounters an external electric field that decreases its kinetic energy from 9480 eV to 8260 eV as the particle moves from position A to position B. The electric potential atA is -43.0 V, and that at B is +25.0 V. Determine the charge of the particle. Include the algebraic sign (+ or -) with your answer
deltaE = q*deltaV
The Attempt at a Solution
I got the solution correct using that formula, I was just wondering why the solution is positive? I thought NEGATIVE charge should flow from low (-43.0 V) to high (+25.0 V) voltage.
Also, does anyone know any good resources to learn the rules of electricity e.g. electrons flow from negative to positive