Riwaj
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$\frac{1 -\cos A}{1 + \cos A} = (\cot A - \csc A)^2$
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The trigonometric identity proof discussed is $\frac{1 - \cos A}{1 + \cos A} = (\cot A - \csc A)^2$. The solution involves converting cotangent and cosecant into sine and cosine, followed by algebraic manipulation. A key step includes multiplying the left side by $\frac{1 - \cos A}{1 - \cos A}$, leading to the expression $\frac{1 - 2\cos A + \cos^2 A}{\sin^2 A}$. This approach successfully demonstrates the equivalence of both sides of the identity.
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Hi Riwaj,Riwaj said:$\frac{1 -\cos A}{1 + \cos A} = (\cot A - \csc A)^2$