Stuck on this simple physics problem.

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Homework Help Overview

The problem involves two buses traveling at constant speeds, with the goal of determining the time it takes for the faster bus to catch up to the slower bus, given their initial distance apart.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the distances traveled by each bus and the time taken, with one suggesting a formula based on their speeds and distances. Others question whether to use a table or a formula for the solution.

Discussion Status

The discussion is ongoing, with participants exploring different approaches to set up the problem. Some have proposed a formula to relate the distances and speeds, while others are still considering how best to represent the information.

Contextual Notes

There is an emphasis on understanding the relationship between the speeds of the buses and the distance separating them, with no consensus on the method to proceed.

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Homework Statement



Two buses are moving at constant speeds, in the same direction, the first at 42 km/h and the second at 54 km/h. They are 18 km apart. How long will it take the second bus to catch up to the first? (4 marks)


Homework Equations



average velocity = d/t

The Attempt at a Solution



Ok well first I tried to make a table of the graph but then I remembered that they were 18 km apart so then I had to rethink and I'm still really stuck on this.
 
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When they catch up, the first bus moves through x km and second bus moves through x + 18 km, and they must have taken the same time to cover that distance.

Can you proceed now?
 
What would be a formula that could solve for this?

Or do I have to use a table?
 
Velocity = x/t. So t = x/v.

Since t is the same

x/v1 = (x+18)/v2

v1 and v2 are given. Solve for x.
 

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