1. The problem statement, all variables and given/known data A uniform beam of 6.6 meters with a weight of 42.67 Newtons is pinned to a wall and supports a weight of 19.62 Newtons.The beam is angled up at 16 degrees and the right end of the beam is supported by a cable attached to the other side of the wall. Find the value of; Tension of the cable, horizontal Pin Joint Force, vertical Pin Joint Force, and the resultant of the H and V force components (where the angle is measured counter clockwise from the horizontal). 2. Relevant equations I am not sure how to start this problem I only know that summing the forces in the x, y and torque direction will be used. 3. The attempt at a solution I tried summing the forces [tex]\sum[/tex]x = H-T=0 ---- so H=T ????? (but what are the numbers) [tex]\sum[/tex]y = V - 42.67Newtons(weight of beam) - 19.62Newtons(weight at end) = 0 (am I missing any???) This would give me V= 62.29 Newtons (If pin joint is the pivot point) [tex]\sum[/tex][tex]\tau[/tex] = H(0)+V(0)-42.67N(3.3cos16)-19.62N(6.6cos16)+T=0 I don't know if this one is right, something does not seem right with the tension part. If this is right that would make the Tension = 259.8N ; which seems too much And because T=H I would think that H would also equal 259.8 Newtons The last part I have no idea what to do.