Student sliding bag along floor in elevator

AI Thread Summary
The discussion revolves around the physics of a student sliding a bag in an elevator, specifically addressing the acceleration involved. The key point is the confusion about why the equation for displacement does not include the term -0.5a_xt^2, as the negative acceleration is already accounted for. The acceleration is expressed as a_x = -α_k (g + a), which is negative, but there is a suggestion that it can be made positive with a different approach. The conversation highlights the nuances of interpreting acceleration in this context. Overall, the participants are exploring the implications of the equations in relation to motion in an elevator.
member 731016
Homework Statement
Pls see below
Relevant Equations
Pls see below
For this problem,
1676877869180.png

The solution is,
1676877943337.png

However, is the reason why they don't do ##-0.5a_xt^2## because the negative of the acceleration has already taken care of itself?

Many thanks!
 
Physics news on Phys.org
The answer seems to make
a_x=-\alpha_k (g+a)<0
negative. You can make it positve one with your setting of ##-0.5a_xt^2##.
 
  • Like
Likes member 731016
anuttarasammyak said:
The answer seems to make
a_x=-\alpha_k (g+a)<0
negative. You can make it positve one with your setting of ##-0.5a_xt^2##.
Than you for your reply @anuttarasammyak !
 
  • Like
Likes anuttarasammyak
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top