Student sliding bag along floor in elevator

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The discussion revolves around the physics of a student sliding a bag in an elevator, specifically addressing the acceleration involved. The key point is the confusion about why the equation for displacement does not include the term -0.5a_xt^2, as the negative acceleration is already accounted for. The acceleration is expressed as a_x = -α_k (g + a), which is negative, but there is a suggestion that it can be made positive with a different approach. The conversation highlights the nuances of interpreting acceleration in this context. Overall, the participants are exploring the implications of the equations in relation to motion in an elevator.
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Homework Statement
Pls see below
Relevant Equations
Pls see below
For this problem,
1676877869180.png

The solution is,
1676877943337.png

However, is the reason why they don't do ##-0.5a_xt^2## because the negative of the acceleration has already taken care of itself?

Many thanks!
 
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The answer seems to make
a_x=-\alpha_k (g+a)<0
negative. You can make it positve one with your setting of ##-0.5a_xt^2##.
 
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anuttarasammyak said:
The answer seems to make
a_x=-\alpha_k (g+a)<0
negative. You can make it positve one with your setting of ##-0.5a_xt^2##.
Than you for your reply @anuttarasammyak !
 
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