Sub-units micro-farad and pico-farad

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SUMMARY

The discussion centers on the relationship between voltage and energy stored in a capacitor, specifically addressing the question of how energy changes when the potential difference across a capacitor is doubled. The relevant equation is U = (1/2)CV², where U represents stored energy, C is capacitance, and V is the voltage. When the voltage is doubled, the energy stored increases by a factor of four, as the voltage is squared in the equation. The sub-units of capacitance, micro-farad and pico-farad, are also defined as smaller units of the farad, which is the standard unit of capacitance.

PREREQUISITES
  • Understanding of capacitance and the farad as a unit of measurement.
  • Familiarity with the equation U = (1/2)CV² for calculating energy stored in capacitors.
  • Knowledge of voltage and its relationship to energy in electrical circuits.
  • Basic concepts of micro-farad and pico-farad as sub-units of capacitance.
NEXT STEPS
  • Study the derivation and applications of the energy formula U = (1/2)CV² in capacitor circuits.
  • Explore the differences between micro-farad and pico-farad in practical applications.
  • Learn about the implications of capacitance in AC and DC circuits.
  • Investigate how varying capacitance affects energy storage in different types of capacitors.
USEFUL FOR

Students studying electrical engineering, electronics enthusiasts, and professionals working with capacitors and energy storage systems.

natural
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1. Homework Statement [/b]
If the p.d across a capacitor is doubled, by what factor does the ehnergy stored change?

Define the farad, the unit of capacitance. Explain the commonly used sub-units micro-farad and pico-farad.
 
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What have you done so far? Show your work. What equation might be useful for question #1?
 
V = Q/C ? i don't really undersatnd the question
 
natural said:
V = Q/C ? i don't really undersatnd the question

That's not an equation for energy. You want U=(1/2)CV^2 where U is the stored energy, C is the capacitance, and V is the potential difference.

It's asking if the potential difference is doubled, how much does the energy stored in the capacitor change. So using that equation, if you double V, what happens to U?
 
ooh ok U doubles
 
natural said:
ooh ok U doubles

NO, look more closely. It's V squared, right?
 
increase by 4?
 
That's better.
 

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