How Does Current Behave in a Discharging RC Circuit?

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SUMMARY

The discussion focuses on calculating the current flowing in a discharging RC circuit after 5 microseconds. A capacitor with a capacitance of 400 pico farads is charged to 10 volts through a 50kΩ resistor. The voltage across the capacitor after 5 microseconds is calculated to be approximately 7.788 volts, leading to a current of 0.156 mA using the formula i = Vr/R. The solution is confirmed as correct, with an alternative expression for current provided as I(t) = I_o e^{-t/τ}.

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brenfox
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Homework Statement


Determine the current flowing when the capacitor has been discharging for 5μs
Capacitance=400 pico farads which is charged to 10v through a 50kΩ resistor.


Homework Equations


Vc = ve-t/CR


The Attempt at a Solution

So Vc =Ve -t/CR
-t/CR = -5*10^-6/400*10^-12*50*10^3
Which equals -0.25 so...
Vc= 10*e-0.25
Vc = 10*0.7788
Vc = 7.788 volts after 5 micro seconds

To find the current flowing after 5 micro seconds
i = Vr/R since Vr=Vc Vc/R = 7.788/50000 = 0.156mA.
Am i in the right ball park with this? Any guidance will be greatly appreciated.
 
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brenfox said:

Homework Statement


Determine the current flowing when the capacitor has been discharging for 5μs
Capacitance=400 pico farads which is charged to 10v through a 50kΩ resistor.


Homework Equations


Vc = ve-t/CR


The Attempt at a Solution

So Vc =Ve -t/CR
-t/CR = -5*10^-6/400*10^-12*50*10^3
Which equals -0.25 so...
Vc= 10*e-0.25
Vc = 10*0.7788
Vc = 7.788 volts after 5 micro seconds

To find the current flowing after 5 micro seconds
i = Vr/R since Vr=Vc Vc/R = 7.788/50000 = 0.156mA.
Am i in the right ball park with this? Any guidance will be greatly appreciated.

Yup, looks fine.

You could also have written the expression for the current ##I(t) = I_o e^{-\frac{t}{\tau}}## using the initial current Io from the initial conditions.
 
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