a 100 pico Farad capacitor C_1 is charged to a potential difference of 50 volts. the charging battery is disconnected and the capacitor is then connected to a second uncharged capacitor C_2. if the potential accross C_1 drops to 35 volts, what was the capacitance of C_2?
capacitance C = Q/V where Q is charge, and V is electric potential in volts
units of capacitance is Farad
The Attempt at a Solution
let C_1 = Q/V_1 where C_1 = 100 pico farads = 100 *10^-12 farads and V_1 = 50 volts
solve for Q to get Q = 5*10^-9 coulombs
let C_2 = Q/V_2 where Q = 5*10^-9 coulombs and V_2 = 35 volts, solve for C_2 to get
capacitance of C_2 = 1.43*10^-10 Farads
did i do this correctly?