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## Homework Statement

a 100 pico Farad capacitor C_1 is charged to a potential difference of 50 volts. the charging battery is disconnected and the capacitor is then connected to a second uncharged capacitor C_2. if the potential across C_1 drops to 35 volts, what was the capacitance of C_2?

## Homework Equations

capacitance C = Q/V where Q is charge, and V is electric potential in volts

units of capacitance is Farad

## The Attempt at a Solution

let C_1 = Q/V_1 where C_1 = 100 pico farads = 100 *10^-12 farads and V_1 = 50 volts

solve for Q to get Q = 5*10^-9 coulombs

let C_2 = Q/V_2 where Q = 5*10^-9 coulombs and V_2 = 35 volts, solve for C_2 to get

capacitance of C_2 = 1.43*10^-10 Farads

did i do this correctly?

thanks