Submerged Fraction of Hollow Glass Sphere

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Homework Help Overview

The problem involves a hollow spherical glass with specified inner and outer radii, and the density of the glass. The question asks for the fraction of the shell that is submerged when it floats in a liquid that is denser than the glass. The context is rooted in buoyancy principles and fluid mechanics.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to equate the buoyant force to the weight of the shell, using the volume of the shell and the displaced fluid. Some participants question the setup and definitions used, particularly regarding the density of the fluid and the meaning of "fraction submerged."

Discussion Status

Participants are actively discussing the setup of the problem, with some providing clarifications on the definitions and variables involved. There is no explicit consensus yet, as various interpretations of the question are being explored.

Contextual Notes

There is ambiguity in the problem statement regarding what is meant by "fraction of the shell submerged," leading to different interpretations among participants. The original poster has expressed confusion about the calculations and the intended meaning of the question.

Fruityloop
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Homework Statement



A hollow, spherical glass has an inner radius of R and an outer radius of 1.2R. The density of the glass is d. What fraction of the shell is submerged when it floats in a liquid of density ρ = 1.5d (1.5 times the density of the glass)? (Assume the interior of the shell is a vacuum.)

Homework Equations



W=ρgh
Volume Sphere = (4/3)πr^3

The Attempt at a Solution



I attempted to set the weight of the water displaced equal to the weight of the shell. (Sum of forces = 0, Bouyont Force - Mass of Shell = 0, BF = Mass of Shell. For weight of shell I used W=ρgh with the volume being the volume of a sphere with r of 1.2R minus volume of a sphere with r of R. For the volume of water displaced I just used some variable fraction multiply by the volume of a sphere equation. ds and Rs then cancel out. I know the answer I'm supposed to get is 0.28, but I keep getting 0.48. Any insight towards a full solution would be hugely appreciated!
 
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The fluid is not water. You have to take its density into account.

ehild
 
I think I took that into account. I had it set up;

BF=Weight of Shell
ρgh (liquid) = ρgh (shell)

(1.5)dgh = dgh

d cancels?
 
What is h? You need to use the volume of the shell to get the weight of the shell and the volume of the outer sphere to get the weight of the displaced fluid.

ehild
 
Oh sorry stupid typo. h is supposed to be V. I am fallowing you, that was my logic. I just don't know how to get from there to my answer >.<
 
The volume of the shell is not the same as the volume of the outer sphere.

ehild
 
Just to add a little noise into the relative peace and calm, when the problem statement asks for "What fraction of the shell is submerged", does it mean what fraction of the mass of the shell is submerged, what fraction of the volume of the shell (sphere!) is submerged, what fraction of the surface area of the shell is submerged, or what fraction of the diameter of the shell is submerged? :devil:
 
gneill said:
Just to add a little noise into the relative peace and calm, when the problem statement asks for "What fraction of the shell is submerged", does it mean what fraction of the mass of the shell is submerged, what fraction of the volume of the shell (sphere!) is submerged, what fraction of the surface area of the shell is submerged, or what fraction of the diameter of the shell is submerged? :devil:

It is fraction of the volume of the sphere, according to the "supposed" answer, but you are right, the question is not clear.

ehild
 
Thanks for the help. I figured it out. @gneill, it is such an elusive question. I wasnt sure exactly what it was asking either.
 

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