Submodules A + B and A intersect B .... Blyth Ch. 2

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The discussion focuses on T. S. Blyth's "Module Theory: An Approach to Linear Algebra," specifically Chapter 2, which addresses the properties of submodules, their intersections, and sums. The claims in question state that the sum of two submodules, denoted as A + B, is the smallest submodule containing both A and B, while the intersection A ∩ B is the largest submodule contained in both. Participants seek formal proofs for these assertions, with one user providing a detailed explanation of how A + B is generated by the union of generating sets for A and B, and suggesting a similar approach for proving the properties of intersections.

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I am reading T. S. Blyth's book "Module Theory: An Approach to Linear Algebra" ... ... and am currently focussed on Chapter 2: Submodules; Intersections and Sums ... ...

I need help with understanding two claims that Blyth makes concerning submodules ...

The relevant text is as follows: ( see end of post for other text that may be relevant)
?temp_hash=73c4113bcdd90e05481e0782497ccecb.png

I have two questions concerning the above text ... ...
Question 1In the above text we read:

" ... ... We know that ##A + B## is the smallest submodule of ##M## that contains both ##A## and ##B##, ... ... "My question is: how exactly do we know this ... ? How would we formally and rigorously prove this ... ?
Question 2In the above text we read:

" ... ... and that ##A \cap B## is the largest submodule contained in both ##A## and ##B##, ... ... "My question is: how exactly do we know this ... ? How would we formally and rigorously prove this ... ?Hope that someone can help with the above two questions ...

Peter

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PS Just in case readers need to reference some of Blyth's definitions or theorems in Chapter 2, I am providing the relevant text as follows:
?temp_hash=73c4113bcdd90e05481e0782497ccecb.png

?temp_hash=73c4113bcdd90e05481e0782497ccecb.png

?temp_hash=73c4113bcdd90e05481e0782497ccecb.png

?temp_hash=73c4113bcdd90e05481e0782497ccecb.png

?temp_hash=73c4113bcdd90e05481e0782497ccecb.png
 

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Math Amateur said:
" ... ... We know that ##A+B## is the smallest submodule of ##M## that contains both ##A## and ##B##, ... ... "
My question is: how exactly do we know this ... ? How would we formally and rigorously prove this ... ?
How are ##A+B## and ##LC(A\cup B)## related?
Then given any submodule ##C \subseteq M## which contains both, ##A## and ##B##, does it contain ##LC(A\cup B)##? And why?

Math Amateur said:
" ... ... and that ##A \cap B## is the largest submodule contained in both ##A## and ##B##, ... ... "
My question is: how exactly do we know this ... ? How would we formally and rigorously prove this ... ?
By theorem 2.1 ##A\cap B## is a submodule of ##M##. Then how are ##A\cap B## and ##LC(A\cap B)## related?
Now given any submodule ##C##, that is contained in ##A## as well as in ##B##, is it contained in ##A\cap B## or ##LC(A\cap B)##? And why?

And at last: If you know all this about any possible submodule ##C \subseteq M##, what does it tell you?
 
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Proof of Q1.
Define A+B\equiv \{a+b\ :\ a\in A\wedge b\in B\}. This is easily shown to be closed under addition and scalar multiplication, and hence a module. It must be a subset of M because M is closed under addition and scalar multiplication and every element of A+B can be expressed as the addition or scalar, multiplication of elements of A and/or B, which are elements of M.

Let ##G_A## and ##G_B## be generating sets for ##A## and ##B## respectively. Then, by the definition of A+B, G_A\cup G_B is a generating set for A+B.

Let C be a submodule of M that contains A and B. Then C contains both G_A and G_B and hence contains G_A\cup G_B. Any element of A+B is a finite linear combination of elements of G_A\cup G_B and, since that union is in C which, being a module, is closed under finite linear combinations, the element must also be in C. So we have A+B\subseteq C.

I imagine the proof for Q2 may be similar but using intersections of generating sets rather than unions. Why not have a go at that and let me know if you get stuck.

Andrew
 
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