Subtracting cartesian products

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SUMMARY

The problem involves calculating the difference between two Cartesian products: (A x B) and (B x C) where A = {1, 2}, B = {3, 4}, and C = {3}. The solution correctly identifies (A x B) as {(1, 3), (1, 4), (2, 3), (2, 4)} and (B x C) as {(3, 3), (4, 3)}. Since there are no overlapping elements between these two sets, the final result remains (A x B), confirming the solution is accurate.

PREREQUISITES
  • Understanding of Cartesian products in set theory
  • Familiarity with set subtraction operations
  • Basic knowledge of mathematical notation and set representation
  • Ability to interpret and manipulate ordered pairs
NEXT STEPS
  • Study advanced set theory concepts, including unions and intersections
  • Explore applications of Cartesian products in database theory
  • Learn about the implications of set operations in programming languages
  • Investigate the use of Cartesian products in data analysis and machine learning
USEFUL FOR

Students in mathematics, computer science, and data analysis, particularly those focusing on set theory and its applications in programming and data manipulation.

nicnicman
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Homework Statement



Let A = {1, 2}, B = {3, 4}, C = {3}

What is (A x B) - (B x C)?

Homework Equations





The Attempt at a Solution



(A x B) - (B x C) = {(1, 3), (1, 4), (2, 3), (2, 4)} - {(3, 3), (4, 3)}
= {(1, 3), (1, 4), (2, 3), (2, 4)}

Since there where no elements in (B x C) that matched any elements in (A x B), I just kept the final answer equal to (A x B).

Would this be the correct way to do this?
 
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nicnicman said:

Homework Statement



Let A = {1, 2}, B = {3, 4}, C = {3}

What is (A x B) - (B x C)?

Homework Equations



The Attempt at a Solution



(A x B) - (B x C) = {(1, 3), (1, 4), (2, 3), (2, 4)} - {(3, 3), (4, 3)}
= {(1, 3), (1, 4), (2, 3), (2, 4)}

Since there where no elements in (B x C) that matched any elements in (A x B), I just kept the final answer equal to (A x B).

Would this be the correct way to do this?
That looks fine to me.
 
Okay, thanks for the help!
 

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