Succesive collisions between a ball and a wall

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Homework Statement
COnversation of momentum.
Relevant Equations
All below
Textbook problem 4.29 about a superball bouncing between two surfaces with speed v0, parts a and b, with printed answers F = mv0^2/l and F = (mv0^2/l)(l/x)^3.

Ignore the letter a. See b.
I disagree with the variation of the velocity. To me, that need to be 2(Vo+V)
" My point is that initial velocity before striking the wall was Vo towards the left and after the collision, the velocity is Vo + 2V towards the right, thus making the change of velocity 2(Vo + V) and not just 2V. " WIfo.
The question arise because of this solution:
Handwritten derivation in a physics frame analysis: a ball with speed v hits a wall moving at V, rebounding with v' in the lab frame, where v' = v + 2V and dv/dt ≈ Δv/Δt = 2V/(2x/v) = v V/x.

I could give an answer equal to the book seeing that V + v ~ v

Is my point above, about the variation of velocity, right? Or am i missing something?
 
The question is poorly posed, because (1) it does not specify the period over which the average is to be taken and (2) it uses but does not define ##l##. If we guess that ##l## is the distance between the walls then the answer to (a) is correct but then how does ##x## differ from ##l##? Perhaps ##l## is supposed to be the initial distance and ##x## the distance at some later time ##t##, ie ##x = x(t)##.

Perhaps it is asking about the average force on each wall over one complete circuit at a later time ##t## when the average distance between the walls is ##x(t)##. In that case the time taken for the circuit will be ##2x(t)/v(t)## where ##v(t)## is calculated by adding to ##v(0)## an amount that is ##2V## times the number of circuits completed since time 0 and ##x(t)## is ##l-Vt##. To work that out we need to work out how many circuits will have been completed by time ##t##, which will depend on the relation between ##l## and ##x##.

Also, as haruspex pointed out, your analysis of the change in velocity is out by ##2v##, as your calculation is of a change in speed, not of velocity.