Sum A+cB of invertible matrices noninvertible?

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The discussion centers on the theorem stating that for invertible square matrices A and B with complex entries, there exists a complex scalar c such that A + cB is noninvertible. The participants explore the proof of this theorem, emphasizing the role of determinants and eigenvalues. Specifically, the hint provided indicates that a non-invertible matrix must have at least one zero eigenvalue, leading to the conclusion that c can be expressed as c = (-λ_a_k)/(-λ_b_k) for some eigenvalues λ_a_k and λ_b_k of matrices A and B, respectively.

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Grothard
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If A and B are both invertible square matrices of the same size with complex entries, there exists a complex scalar c such that A+cB is noninvertible.

I know this to be true, but I can't prove it. I tried working with determinants, but a specific selection of c can only get rid of one entry in A+cB, which is not enough since the matrices do not have to be triangular. How would one go about proving this theorem?
 
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Prove this theorem by construction. Hint: A non-invertible matrix has at least one zero eigenvalue.
 
So c = (-λ_a_k)/(-λ_b_k), thanks!
 

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