I am having trouble finding [tex]\sum \frac{(-1)^n}{n^2} [/tex]. (from n=1 to n=infinity)(adsbygoogle = window.adsbygoogle || []).push({});

I know that [tex]\sum \frac{1}{n^2}[/tex] is [tex]\frac{\pi^2}{6} [/tex]. But the sum I need is slightly different than that, it is alternating....

Any ideas/help would be appreciated! Thx

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# Sum of an infinite alternating series

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