Sum of Geometric Series with cosine?

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Homework Help Overview

The discussion revolves around the sum of a geometric series involving the expression pi^(n/2)*cos(n*pi). Participants are exploring the convergence or divergence of the series as n approaches infinity.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning how to approach the problem, particularly whether to use the Squeeze Theorem or D'Alembert's rule for convergence. There is also discussion about the behavior of the cosine function in the series.

Discussion Status

Some participants have offered insights into the convergence of the series, noting the alternating nature of the cosine function and its implications for divergence. There is an ongoing exploration of the notation and the conditions for divergence.

Contextual Notes

There are mentions of potential confusion regarding notation and the need to consider absolute values in the context of convergence tests. The participants are navigating through the assumptions related to the series' behavior.

dan38
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Homework Statement


With a series like:
pi^(n/2)*cos(n*pi)

How am I meant to approach this?
Do I use the Squeeze Theorem?


Homework Equations





The Attempt at a Solution

 
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I believe you are trying to find the sum as n->infinity?

If so, you should start by checking whether the series converges or diverges.
 
Hi dan38
As Infinitum suggested, you probably are looking for convergence/divergence of the serie
I suppose you are being confused by the cos 'trick'.
But look at is closely.. what possible values do you have for cos(n∏) ?
1, -1, 1, -1, ... that is, (-1)^n
Are you familiar with D'Alembert's rule to decide on convergence ?

Cheers...
 
ah I see
so then it would become

(pi)^0.5 * (pi)^n * (-1)^n

pi^0.5 * ( - pi )^n

-pi^1.5 * ( - pi )^(n-1)

Of the form required
where a = -pi^1.5 and r = -pi

since r > 1
then it is divergent?
 
Well you're notation is confusing, you are supposed to use absolute values and somehow you get to -∏,
but yes, you would get to ∏>1 and therefore it diverges

Cheers...
 

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