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Please help me in solving the problem,
find the sum
Sum{r=2 to infinity} (von Mangoldt(r)-1)/r
Your help is appreciated.
find the sum
Sum{r=2 to infinity} (von Mangoldt(r)-1)/r
Your help is appreciated.
[tex]\frac1n \sum_{k=1}^n\Lambda(k)=1+o(1/\log n)[/tex]hi mhill,
can you prove that the series is divergent?
My post addressed the case where n runs from 2 to infinity, which diverges.when n is a prime or prime power, the summation is okay.
but suppose when n=6, then the sum is (von Mangoldt(6) -1)/6 , which is = -1/6,
as n runs from 2 to infinity,can we settle the problem of convergency or divergency?
Right, right... yeah, I calculated it for numerator [itex]\Lambda[/itex] first, forgetting about the -1 term, and when I added it back in forgot that part.Is something missing ?