Deriving the PGF for Binomial Distribution using Combinations

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The discussion focuses on deriving the probability generating function (PGF) for the binomial distribution. The initial expression presented is \sum^{n}_{x=0}(nCx)(\frac{sp}{1-p})^x, but there is confusion about missing terms. A suggestion is made to correct the expression to \sum_{x = 0}^n \binom{n}{x} (sp)^x (1 - p)^{n - x}. The derivation is linked to the binomial theorem, which states that (x + y)^n can be expanded using combinations. The conversation emphasizes the importance of including all relevant terms to achieve the correct PGF.
Darth Frodo
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Homework Statement



I'm trying to derive the PGF for the Binomial.


The Attempt at a Solution



I have it whittled down to \sum^{n}_{x=0}(nCx)(\frac{sp}{1-p})^x

I just don't know how to simplify this further. Any help is most appreciated.
 
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I think you lost some ##(1 - p)##s there, are you sure you didn't mean ##\sum_{x = 0}^n \binom{n}{x} (sp)^x (1 - p)^{n - x}##?

The result should follow from the binomial theorem,
$$ (x + y )^n = \sum_{k = 0}^n \binom{n}{k} x^{n-k} y^k. $$
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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