Summing a Geometric Series with Variable Exponents

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SUMMARY

The discussion focuses on summing the series defined by the formula ∑ n/(2^n), which represents a geometric series with variable exponents. Participants suggest analyzing the first few terms to identify a pattern and propose defining the function f(x) = x^n/2^n. The derivative of this function, evaluated at x=1, is indicated as a potential method for deriving the sum of the series.

PREREQUISITES
  • Understanding of geometric series and convergence
  • Familiarity with calculus, specifically differentiation
  • Knowledge of summation notation and series manipulation
  • Basic algebraic skills for pattern recognition
NEXT STEPS
  • Study the properties of geometric series and their convergence criteria
  • Learn about the application of derivatives in summation techniques
  • Explore the concept of power series and their relationship to geometric series
  • Investigate advanced techniques for summing infinite series
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Students studying calculus, mathematicians interested in series summation, and educators seeking methods to teach geometric series concepts.

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Homework Statement



1/2 + 2/4 + 3/8 + 4/16 + 5/32 + ...

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The Attempt at a Solution



The only headway I've made is that this is ∑ n/(2^n). how do I go about summing this?
 
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how about starting by adding up the first few terms and looking for a pattern with n terms
 
Define f(x)=x^n/2^n. If you find that then your sum just might be related to f'(x) at x=1.
 

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