Superposition, amplitudes and superposed waves.

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SUMMARY

The discussion focuses on calculating the amplitudes and intensities of superposed waves in physics. For mutually coherent waves with intensities of 4 unit² and 9 unit², the resultant amplitude is derived from the formula where intensity is proportional to the amplitude squared, resulting in an intensity of 25 unit². In the case of mutually incoherent waves with amplitudes of 3 unit and 4 unit, the intensity is calculated using the formula I = I1 + I2, leading to a total intensity of 25 unit². The phase difference plays a crucial role in determining the resultant intensity for incoherent waves.

PREREQUISITES
  • Understanding of harmonic waves and their properties
  • Knowledge of the relationship between intensity and amplitude in wave physics
  • Familiarity with the concept of coherence in wave mechanics
  • Basic mathematical skills for squaring numbers and applying formulas
NEXT STEPS
  • Study the principles of wave superposition and coherence
  • Learn about the mathematical derivation of intensity from amplitude in wave physics
  • Explore the effects of phase differences on wave interference
  • Investigate real-world applications of wave superposition in acoustics and optics
USEFUL FOR

Students studying physics, particularly those focusing on wave mechanics, as well as educators and anyone interested in understanding the principles of wave superposition and interference.

isabelle87
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First off:
Sorry. I'm a Norwegian girl, so my English may not be of very good quality.
Now that's said...

I have this problem to solve.
Only thing is - I don't have a clue how!
I'm no good at physics, but unfortunately I have to have this class.

Anyway.
My problem is this:

Task 1a)
Two harmonic waves are mutually coherent.
One wave has an intensity of 4 unit^2,
the other wave has the intensity of 9 unit ^2,
their superposition wave will have an amplitude of

Task 1b)
Two waves are mutually incoherent.
One wave has an amplitude of 3 unit,
the other wave has an amplitude of 4 unit.
The intensity for the superposed wave should be?

How do I calculate this?
What formula am I suppose to use?
And if you only wan't to give me the formula,
can you please explain what the different letters, symbols and stuff means (so that I can solve it myself, if you don't want to give me the direct answer?)
 
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hmmm

1a)the intensity is propotional to the amplitude squared. if they're mutually coherent you add the amplitudes and square the resultant (ans= 25 unit^2 i think)

1b)if mutually incoherent, there's a phase difference. so for all you know, a peak of one wave could coincide with a trough of the other. The resultant amplitude is anywhere from 1 to 7 (ie. intensity=1 to 49)
 
Thank you for your reply, but did you perhaps overlook that it said "9 unit^2"?

Anyway.
If I now do this your way it'll be like this rigth?
9^2 + 4^2 = 97
And you believed I should square the result so that the final answer would be 97^2.

I don't know if this is right,
but either way I'm really thankful for your advice/opinion.
It's certainly worth a try!

:D
 
The second answer you gave me seems to be wrong,
I found out to crack it on my own.
Or... At least i think I did ;)

Because the waves are incoherant I have to use the formula:
I = I1 + I2
= 3^2 + 4^2
= 25

The intensity for the superposed wave should be 25.
 
^^ Not sure if that's correct TBH.

I(total) is infact I1+I2+(A1*A2)cos(X)

where X is the phase difference between the two waves and A is the amplitude. Incoherent waves, by definition, have a difference in phase.
 

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