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Superposition net gravitational force

  1. Jun 12, 2006 #1
    I would appreciate any help on this problem:

    In Fig. 14-18a, a square of edge length .232m is formed by four spheres of masses m1 = .00372 kg, m2 = .00958 kg, m3 = .00408 kg, and m4 = .00835 kg. In unit-vector notation, what is the net gravitational force from them on a central sphere with mass m5 = .00424 kg?

    [​IMG]

    I started out by using F = G*Ma*Mb/r^2. So for the x-direction, it would be something like:

    Fi = G*M3*M4/r^2 + G*M1*M2/r^2, and similar things for the y-direction.

    But I don't know how to include the m5 into my equations. Do I have to involve angles and trig functions?
     
  2. jcsd
  3. Jun 12, 2006 #2
    Okay, here's the first thing that needs to happen. Just as a forwarning, trig will be used to the fullest extent. Remeber that when you want to find the net gravitational force, you don't include the particle that you are ovbserving. The only part that it plays is the distance from the other particles. Also, remeber that particles on either side of a central particle have cancelling effects, depending on the masses and the radial distances.
     
  4. Jun 12, 2006 #3
    Be careful with your components in the vector notaion. Remeber that vertical components of force vectors have nothing to do with the horizontal with tregards to the algebraic setup.
     
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