Superposition of 2 Waves: Equation

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SUMMARY

The equation for the superposition of two waves is expressed as D1 + D2 = 2Acos[(k1-k2)x/2 - (ω1 - ω2)t/2]*sin[(k1 + k2)x/2 - (ω1 + ω2)t/2]. The discussion highlights the challenge of expressing this equation solely in terms of angular frequencies ω1 and ω2, as the wave numbers k1 and k2 also play a crucial role. Participants debated whether it is acceptable to omit k values when the focus is on angular frequencies. The consensus indicates that the equation can be manipulated, but care must be taken to maintain the integrity of the wave characteristics.

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  • Understanding of wave mechanics and superposition principles
  • Familiarity with trigonometric identities and their application in wave equations
  • Knowledge of angular frequency (ω) and wave number (k) concepts
  • Basic algebraic manipulation skills for equation transformation
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  • Explore the implications of different angular frequencies on wave behavior
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Homework Statement


What is the equation for the superposition of 2 waves?

Homework Equations


The Attempt at a Solution


Displacement of the first wave is D1 = Asin(k1x - ω1t)

Displacement of second wave is D2= Asin(k2x - ω2t)

Add together: D1 + D2 = 2Acos[(k1-k2)x/2 - (ω1 - ω2)t/2]*sin[(k1 + k2)x/2 - (ω1 + ω2)t/2]

But this isn't in terms of what the problem is asking! Help, can the form be changed somehow?

Is there a way to reduce the k1 and k2 so that it is in that form?
 
Last edited:
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But it IS in terms of w1-w2 and w1+w2! Maybe the question meant that you could use y=Asin(w*t) instead of y=Asin(kx-wt), but otherwise, your work is correct.
 
Good point. But if the waves have different angular frequencies, wouldn't k be different? I don't see how you can just leave it out.

When a question asks for something in terms of w1 and w2, doesn't that mean I shouldn't have anything else in there?
 

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